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Haryana PMT Haryana PMT Solved Paper-2006

  • question_answer
    A_ particle   moves   with   a   velocity      \[\text{(5}\mathbf{\hat{i}}\text{-3\hat{J}+6\hat{K})}\]  m/s under the influence of a constant force \[\overrightarrow{\mathbf{F}}\text{=(10}\mathbf{\hat{i}}\text{+10}\mathbf{\hat{J}}\text{+12}\mathbf{\hat{K}}\text{)}\] instantaneous power applied to the particle is:

    A)                  200 J/s                                

    B)  40J/s

    C)                  140 J/s                                

    D)  170 J/s

    Correct Answer: C

    Solution :

                    \[\overrightarrow{v}=(5\hat{i}-3\hat{j}+6\hat{k})m/s\] \[\overrightarrow{F}=(10\hat{i}+10\hat{j}+20\hat{k})N\] \[\therefore \] Power       \[\overrightarrow{P}=\overrightarrow{F}.\overrightarrow{v}\] \[=(10\hat{i}+10\hat{j}+20\hat{k}).(5\hat{i}-3\hat{j}+6\hat{k})\] \[=50-30+120\] \[=140W=140J/s\]


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