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Haryana PMT Haryana PMT Solved Paper-2007

  • question_answer
    What is the Q-value of the reaction  \[p{{+}^{7}}Li{{\xrightarrow{{}}}^{4}}He{{+}^{4}}He\] The atomic masses of\[{{~}^{1}}H{{,}^{4}}He\] and \[^{7}Li\]are 1.007825\[u\], 4.002603 \[u\] and 7.016004 \[u\] respectively

    A)  17.35 MeV                        

    B)  18.06 MeV

    C)  177.35 MeV                      

    D)  170.35 MeV

    Correct Answer: A

    Solution :

                    Key Idea The total energy released in reaction (Q) 15 equal to the difference in kinetic energy of the final particles and of initial particles. The total mass of the initial particles                 \[{{m}_{i}}=1.007825+7.016004\] \[=8.023829\text{ }u,\] and the total mass of final particles                 \[{{m}_{f}}=2\times 4.002603\]                 \[=8.005206u\] Difference between initial and final mass of particles \[\Delta m={{m}_{i}}-{{m}_{f}}=8.023829-8.005206\]                 \[=0.018623u\] The Q-value is given by                 \[Q=(\Delta m){{c}^{2}}\]                 \[=0.018623\times 931.5\]                 \[=17.35MeV\]


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