Haryana PMT Haryana PMT Solved Paper-2007

  • question_answer
    If acceleration of a panicle at any time is given by \[a=2t+5\] Calculate the velocity after 5 s, if it starts from rest.

    A)  50 m/s                                

    B)  25 m/s

    C)  100 m/s                              

    D)  75 m/s

    Correct Answer: A

    Solution :

                    \[a=2t+5\] or            \[\frac{dv}{dt}=2t+5\] or            \[dv=(2t+5)dt\] ?(i) Integrating Eq. (i) on both sides within the limits                 \[\int_{0}^{v}{dv=}\int_{0}^{5}{(2t+5)dt}\] or            \[v=\left[ \frac{2{{t}^{2}}}{2}+5t \right]_{0}^{5}\]                 \[=[5\times 5+5\times 5]=50m/s\]


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