Haryana PMT Haryana PMT Solved Paper-2007

  • question_answer
    The reaction follows the mechanism\[A+BAB\,\,\,(fast)\]\[AB+B\xrightarrow{{{k}_{2}}}A+{{B}_{2}}\,\,(slow)\]then rate law is

    A)  \[r=k[A][B]\]

    B)  \[r=k[AB][B]\]

    C)  \[r=k[A]{{[B]}^{2}}\]

    D)  \[r=k{{[A]}^{2}}[B]\]

    Correct Answer: C

    Solution :

                    Mechanism, \[A+B\overset{{{k}_{1}}}{\mathop{\rightleftharpoons }}\,AB\,\,\,(fast)\] \[AB+B\overset{{{k}_{2}}}{\mathop{\rightleftharpoons }}\,A+{{B}_{2}}\,\,\,(slow)\] rate law \[={{k}_{2}}[AB][B]\] For fast reaction (steady state step)                 \[{{k}_{1}}[A][B]={{k}_{1}}[AB]\]                 \[[AB]=\frac{{{k}_{1}}[A][B]}{{{k}_{-1}}}\] The value of \[[AB]\] put into rate law Rate law\[=\frac{{{k}_{2}}{{k}_{1}}}{{{k}_{-1}}}[A]{{[B]}^{2}}\]                 \[=k[A]{{[B]}^{2}}\]


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