A) \[1:2\]
B) \[1:3\]
C) \[2:3\]
D) \[4:1\]
Correct Answer: A
Solution :
\[[Co{{(N{{H}_{3}})}_{5}}Cl]C{{l}_{2}}\] give three ions, \[{{[Co{{(N{{H}_{3}})}_{5}}Cl]}^{2+}}\], \[2C{{l}^{-}}\], ie, \[1:2\]
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