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Haryana PMT Haryana PMT Solved Paper-2008

  • question_answer
    For angles of projection of a projectile at  angles (45° - \[\text{ }\!\!\theta\!\!\text{ }\]) and (45° + \[\text{ }\!\!\theta\!\!\text{ }\]), the horizontal                ranges described by the projectile are in the       ratio of

    A)  1 : 1                                      

    B)  2 : 3

    C)  1: 2                                       

    D)  2 :1

    Correct Answer: A

    Solution :

                    The projectiles are projected at angles \[({{45}^{o}}-\theta )\] and \[({{45}^{o}}+\theta )\]which are complementary to each other ie, two angles add up to give \[{{90}^{o}}\]. Hence, horizontal ranges will be equal. Thus, the required ratio is \[1:1\].


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