A) 12
B) zero
C) 1
D) 6
Correct Answer: D
Solution :
Let \[{{\lambda }_{1}}=5.0m,\] \[v=330m/s\] and \[{{\lambda }_{2}}=5.5m\] The relation between frequency, wavelength and velocity is given by \[v=n\lambda \] \[\Rightarrow \] \[n=\frac{v}{\lambda }\] ?..(i) The frequency corresponding to wavelength \[{{\lambda }_{1}}\]. \[{{n}_{1}}=\frac{v}{{{\lambda }_{1}}}=\frac{330}{5.0}=66Hz\] The frequency corresponding to wavelength \[{{\lambda }_{2}}\], \[{{n}_{2}}=\frac{v}{{{\lambda }_{2}}}=\frac{330}{5.5}=60Hz\] Hence, number of beats per second \[={{n}_{1}}-{{n}_{2}}\] \[=66-60\] \[=6\]
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