A) 0, 0
B) 0, 10 m/s
C) 10 m/s, 10 m/s
D) 10 m/s, 0
Correct Answer: B
Solution :
Average velocity is defined as the ratio of displacement to time taken while the average speed of a particle in a given interval of time is defined as the ratio of distance travelled to the time taken. On a circular path in completing one turn, the distance travelled is 2nr while displacement is zero. Hence, average velocity \[\frac{displacement}{time\,-\text{interval}}\] \[=\frac{0}{t}=0\] Average speed \[=\frac{\text{Distance}}{Time-\text{interval}}\] \[=\frac{2\pi r}{t}=\frac{2\times 3.14\times 100}{62.8}\] \[=10m/s\]
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