A) \[N{{a}^{+}},C{{l}^{-}},{{H}_{3}}{{O}^{+}}\]
B) \[N{{a}^{+}},C{{l}^{-}},{{H}_{2}}O\]
C) \[N{{a}^{+}},C{{l}^{-}},O{{H}^{-}}\]
D) \[{{H}^{+}},{{H}_{3}}{{O}^{+}}\]
Correct Answer: B
Solution :
\[HCl\]is completely neutralised by \[NaOH\] solution gives \[NaCl\] (salt). \[HCl+NaOHNaCl+{{H}_{2}}O\] \[HCl{{H}^{+}}+C{{l}^{-}}\] \[NaOHN{{a}^{+}}+O{{H}^{-}}\] \[{{H}^{+}}+O{{H}^{-}}\xrightarrow{{}}{{H}_{2}}O\] Hence, the resulting solution contains \[N{{a}^{+}}\], \[C{{l}^{-}}\]and \[{{H}_{2}}O\].
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