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Haryana PMT Haryana PMT Solved Paper-2008

  • question_answer
    For the reaction,\[C(s)+C{{O}_{2}}(g)2CO(g)\]the partial pressure of \[C{{O}_{2}}\] and \[CO\] are 2.0 and 4.0 arm respectively then equilibrium \[{{K}_{p}}\] for the reaction will be

    A)  \[0.5\]                                 

    B)  \[8.0\]

    C)  \[4.0\]                                 

    D)  \[32\]

    Correct Answer: B

    Solution :

                    For the reaction,\[C(s)+C{{O}_{2}}(g)2CO(g)\] \[{{K}_{p}}=\frac{\text{partial pressure of gasseous products }}{\text{partial pressure of gasseous reactans }}\]\[=\frac{P_{CO}^{2}}{{{P}_{C{{O}_{2}}}}}=\frac{4\times 4}{2}=8\]


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