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Haryana PMT Haryana PMT Solved Paper-2008

  • question_answer
    pH of \[HCl\] (cone.\[0.1mol/L\]) is one. Compute the pH of 0.05 mol/L solution of \[{{H}_{2}}S{{O}_{4}}\].

    A)  \[0.05\]             

    B)  \[0.5\]

    C)  \[1\]                                    

    D)  \[2\]   

    Correct Answer: C

    Solution :

                    Normality of \[{{H}_{2}}S{{O}_{4}}=0.05\times 2\] \[=0.1N\] \[\therefore \] \[pH=-\log [{{H}^{+}}]\]                 \[=-\log [{{10}^{-1}}]\] \[\because \]     \[=1\]


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