A) electrophilic addition reaction
B) nucleophilic addition reaction
C) free radical addition reaction
D) electrophilic substitution reaction
Correct Answer: A
Solution :
\[HBr\xrightarrow{{}}{{H}^{+}}+B{{r}^{-}}\] \[C{{H}_{2}}=CHC{{H}_{3}}\xrightarrow{+{{H}^{+}}(electrophile)}\] \[C{{H}_{3}}-\overset{+}{\mathop{C}}\,HC{{H}_{3}}\xrightarrow{+B{{r}^{-}}}C{{H}_{3}}-\underset{Br}{\mathop{\underset{|}{\mathop{C}}\,}}\,HC{{H}_{3}}\] Electrophilic addition reaction
You need to login to perform this action.
You will be redirected in
3 sec
