A) \[[Xe]6{{s}^{2}}\]
B) \[[Ar]4{{s}^{2}}3{{d}^{10}}\]
C) \[1{{s}^{2}}\]
D) \[[Rn]7{{s}^{2}}6{{d}^{1}}5{{f}^{14}}\]
Correct Answer: C
Solution :
\[1{{s}^{2}}\] has highest value of ionisation potential, because of outermost electrons are very near to nucleus,
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