Haryana PMT Haryana PMT Solved Paper-2009

  • question_answer
    In the circuit shown the equivalent resistance between A and B is

    A)  27 \[\Omega \]                               

    B)  18 \[\Omega \]

    C)  90\[\Omega \]                                

    D)  3\[\Omega \]

    Correct Answer: D

    Solution :

                    The three resistances between A and B are parallel, \[\frac{1}{{{R}_{comb}}}=\frac{1}{{{R}_{1}}}+\frac{1}{{{R}_{2}}}+\frac{1}{{{R}_{3}}}\] \[=\frac{1}{9}+\frac{1}{9}+\frac{1}{9}\] \[\frac{1}{{{R}_{comb}}}=\frac{3}{9}\] \[\Rightarrow \] \[{{R}_{comb}}=3\Omega \]


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