A) \[HCO_{3}^{-}\]
B) \[CO_{3}^{2-}\]
C) \[NO_{3}^{-}\]
D) \[SO_{4}^{2-}\]
Correct Answer: A
Solution :
Since the sodium salt on treatment with \[MgC{{l}_{2}}\] gives white ppt on heating, the salt must be sodium bicarbonate and the reactions are as follows \[\underset{sodium\,bicarbonate}{\mathop{2NaHC{{O}_{3}}}}\,+MgC{{l}_{2}}\xrightarrow{{}}\underset{magnesium\,bicarbonate}{\mathop{Mg{{(HC{{O}_{3}})}_{2}}}}\,\] \[+2NaCl\] \[Mg{{(HC{{O}_{3}})}_{2}}\xrightarrow{\Delta }\underset{white\,ppt}{\mathop{MgC{{O}_{3}}}}\,\downarrow +{{H}_{2}}O+C{{O}_{2}}\]
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