Haryana PMT Haryana PMT Solved Paper-2010

  • question_answer
    If the work done in blowing a bubble of volume V is W, then the work done in blowing the bubble of volume 2 V from the same soap solution will be

    A)  W/2                                     

    B)  \[\sqrt{2}W\]

    C)  \[\sqrt[3]{2}W\]                             

    D)  \[\sqrt[3]{4}W\]

    Correct Answer: D

    Solution :

                    Work done to form a soap bubble \[W=8\pi {{R}^{2}}T\]                 \[\therefore \]  \[W\propto {{V}^{2/3}}\]  [As  \[V\propto {{R}^{3}}\]  \[\therefore \]  \[R\propto {{V}^{1/3}}\]]                 \[\frac{{{W}_{2}}}{{{W}_{1}}}={{\left[ \frac{{{V}_{2}}}{{{V}_{1}}} \right]}^{2/3}}\]                 \[={{(2)}^{2/3}}\]                 \[\Rightarrow \]               \[{{W}_{2}}={{(4)}^{1/3}}W\]


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