Haryana PMT Haryana PMT Solved Paper-2010

  • question_answer
    When a ray is refracted from one medium to another, the wavelength changes from \[6000\overset{\text{o}}{\mathop{\text{A}}}\,\] to \[4000\overset{\text{o}}{\mathop{\text{A}}}\,\]. The critical angle for the interface will be

    A)  \[{{\cos }^{-1}}\left( \frac{2}{3} \right)\]                              

    B)  \[{{\cos }^{-1}}\left( \frac{2}{\sqrt{3}} \right)\]

    C)  \[{{\cos }^{-1}}\left( \frac{2}{3} \right)\]                              

    D)  \[{{\cos }^{-1}}\left( \frac{2}{\sqrt{3}} \right)\]

    Correct Answer: C

    Solution :

                    As      \[_{1}{{\mu }_{2}}=\frac{1}{\sin \,C}\] \[\Rightarrow \]               \[\frac{{{\mu }_{2}}}{{{\mu }_{1}}}=\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\frac{1}{\sin \,C}\] \[\Rightarrow \]               \[\frac{6000}{4000}=\frac{1}{\sin \,C}\] \[\Rightarrow \]               \[C={{\sin }^{-1}}\left( \frac{2}{3} \right)\]


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