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Haryana PMT Haryana PMT Solved Paper-2010

  • question_answer
    Light of wavelength 500 nm is used to form interference pattern in Youngs double slit experiment. A uniform glass plate of refractive index 1.5 and thickness 0.1 mm is introduced in the path of one of the interfering beams. The number of fringes which will shift the cross-wire due to this is

    A)  100                                       

    B)  200

    C)  300                                       

    D)  400

    Correct Answer: A

    Solution :

                    The number of fringes shifting is decided by the extra path difference produced by introducing the glass plate.                      The extra path difference is \[(\mu -1)t=n\lambda \] or \[(1.5-1)\times 0.1\times {{10}^{-3}}=n\times 500\times {{10}^{-9}}\] \[\Rightarrow \]               \[n=100\]


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