A) \[3\times {{10}^{8}}\]
B) \[\left( \frac{3}{\sqrt{2}} \right)\times {{10}^{8}}\]
C) \[\sqrt{3}\times {{10}^{8}}\]
D) \[0.5\times {{10}^{8}}\]
Correct Answer: C
Solution :
From Brewsters law, \[\mu =\tan \,{{i}_{p}}\] \[\Rightarrow \] \[\frac{v}{c}=\tan \,{{60}^{o}}=\sqrt{3}\] \[\Rightarrow \] \[v=\frac{c}{\sqrt{3}}=\frac{3\times {{10}^{8}}}{\sqrt{3}}=\sqrt{3}\times {{10}^{8}}m/s\]
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