A) +10%
B) + 46%
C) -10%
D) - 40%
Correct Answer: B
Solution :
Volume of liquid coming out of the tube per Second is \[V=\frac{p\pi {{r}^{4}}}{8\eta l}\] \[\Rightarrow \] \[\frac{{{V}_{2}}}{{{V}_{1}}}={{\left[ \frac{{{r}_{2}}}{{{r}_{1}}} \right]}^{4}}\] \[\Rightarrow \] \[{{V}_{2}}={{V}_{1}}{{\left[ \frac{110}{100} \right]}^{4}}\] \[={{V}_{1}}{{(1.1)}^{4}}=1.4641V\] \[\frac{\Delta V}{V}=\frac{{{V}_{2}}-{{V}_{1}}}{V}=\frac{1.4641\,\,V-V}{V}\] \[=0.46\] or \[46%\]
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