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Haryana PMT Haryana PMT Solved Paper-2010

  • question_answer
    Nitrogen has the electronic configuration \[1{{s}^{2}},2{{s}^{2}},2p_{x}^{1}2p_{y}^{1}2p_{z}^{1}\] and not  \[1{{s}^{2}},2{{s}^{2}},2p_{x}^{2}2p_{y}^{1}2p_{z}^{0}\], which is determined by

    A)  Pauli exclusion principle

    B)  Aufbau principle

    C)  Hunds rule

    D)  Uncertainty principle

    Correct Answer: C

    Solution :

                    According to Hunds rule electron pairing in p, d and f orbitals cannot occur until each orbital of a given subshell is singly occupied. Hence,     \[1{{s}^{2}},2{{s}^{2}},2p_{x}^{1}2p_{y}^{1}2p_{z}^{0}\]     electronic configuration is not possible for nitrogen;


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