2. Solved Papers
  3. Haryana PMT

Haryana PMT Haryana PMT Solved Paper-2011

  • question_answer
    Photons of energy 6 eV are incident on a potassium surface of work function 2.1 eV. The stopping potential will be

    A)                  -8.1V                                   

    B)  -3.9V

    C)                  -6V                                       

    D)  -2.1V

    Correct Answer: B

    Solution :

                    \[{{E}_{k}}=hv-\phi \]                 = 6-21                 = 3.9 eV                 Stopping potential \[\frac{{{E}_{k}}}{e}\]                 \[\text{=-}\frac{\text{3}\text{.9eV}}{\text{e}}\text{=-3}\text{.9V}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner