A) 4 s
B) 2 s
C) 0.5 s
D) 0.25 s
Correct Answer: B
Solution :
For each half, mass is half and length is half As, \[\begin{align} & \\ & I\frac{m{{l}^{2}}}{\begin{align} & 12 \\ & \\ \end{align}} \\ \end{align}\] \[\therefore \] I becomes \[\frac{1}{8}th\] Also, M becomes half As \[t=2\pi \sqrt{\frac{I}{MB}}\] \[\therefore \] T becomes,\[\sqrt{\frac{1/8}{1/2}\,}\] time = \[\frac{1}{2}\] time New time period \[=\frac{1}{2}\times 4s=2s\]
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