A) 40 \[\mu F\]
B) 20 \[\mu F\]
C) 30 \[\mu F\]
D) 10 \[\mu F\]
Correct Answer: D
Solution :
Two-two capacitors in upper and lower arms are joined in series, their equivalent capacitance in series. \[\frac{1}{C}=\frac{1}{10}+\frac{1}{10}\] or \[\frac{1}{C}=\frac{1}{10}\] Hence, C = 5\[\mu \]F So, total capacitance upper and lower part of system now (in parallel) \[C=5\mu F+5\mu F=10\mu F\]
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