A) v= 4gt
B) v= 5gt
C) v= 2gt
D) v= 16gr
Correct Answer: A
Solution :
\[\frac{v}{t}=\frac{{{v}_{1}}-{{v}_{2}}}{{{t}_{2}}-{{t}_{1}}}=\frac{\sqrt{2{{a}_{1}}s}-\sqrt{2{{a}_{2}}s}}{\sqrt{\frac{2s}{{{a}_{2}}}}-\sqrt{\frac{2s}{{{a}_{1}}}}}\] \[\Rightarrow \] \[v=(\sqrt{{{a}_{1}}{{a}_{2}}})t\] \[\Rightarrow \] \[v=\sqrt{(2g)}(8g)t\] \[\Rightarrow \] \[v=\sqrt{16{{g}^{2}}t}\] \[\Rightarrow \,\]\[v=4gt\]
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