A) 0.72m
B) 0.12m
C) 0.18m
D) 0.36m
Correct Answer: B
Solution :
\[\lambda =\frac{v}{n}=\frac{360}{500}\] \[=\frac{18}{25}m\] \[\Delta =\frac{\lambda }{2\pi }\Delta \phi \] \[=\frac{18}{25(2\pi )}\times \frac{\pi }{3}\] \[=0.12m\]
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