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Haryana PMT Haryana PMT Solved Paper-2011

  • question_answer
    The ratio of the energy of a photon of \[~2000\overset{\text{o}}{\mathop{\text{A}}}\,\] wavelength radiation to that of \[~4000\overset{\text{o}}{\mathop{\text{A}}}\,\] radiation is

    A)  \[\frac{1}{2}\]                                  

    B)  \[\frac{1}{4}\]

    C)  \[2\]                                    

    D)  \[4\]

    Correct Answer: C

    Solution :

                    \[E=hv=h\frac{c}{\lambda }\] \[\Rightarrow \]               \[E\alpha \frac{1}{\lambda }\] \[\Rightarrow \]               \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}=\frac{4000}{2000}=2\]


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