A)
B)
C)
D) \[\underset{COOH}{\overset{COOH}{\mathop{|}}}\,\]
Correct Answer: B
Solution :
Benzoic acid, oxalic acid and picric acid are sufficient acidic to evolve \[C{{O}_{2}}\] but 3-methoxy phenol is comparatively less acidic hence it does not evolve \[C{{O}_{2}}\] with \[NaHC{{O}_{3}}\].
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