A) 1 mg
B) 1 kg
C) 3.6kg
D) 3.3kg
Correct Answer: C
Solution :
\[E=100\text{ }kWh\text{ }=100\times 1000\times 60\times 60J\] \[\text{E}=\text{Vq }=\text{33q}\] So, \[q=\frac{36x{{10}^{7}}}{33}C\] Also \[m=Zq\] \[=\frac{0.33\times {{10}^{-6}}\,\times 36\times {{10}^{7}}}{33}\] \[=3.6kg\]You need to login to perform this action.
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