A) 349, 174.5
B) 174.5, 349
C) 349, 698
D) 698, 349
Correct Answer: B
Solution :
At neutral temperature, dE /dt = 0; so \[\frac{dE}{dt}=2164-6.2\times 2\times {{t}_{n}}=0\]or\[{{t}_{n}}={{174.5}^{o}}C\] At temperature of inversion \[e=0=2164{{t}_{i}}-6.2_{i}^{2}\] Hence \[{{t}_{i}}~=349{}^\circ C\]You need to login to perform this action.
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