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Haryana PMT Haryana PMT Solved Paper-2011

  • question_answer
    A hydrogen gas electrode has potential of \[-0.118V\]when \[{{H}_{2}}\]as is bubbled at \[298K\] and \[1\text{ }arm\]in \[HCl\] solution. The pH of \[HCl\] solution is

    A)  \[2\]                                    

    B)  \[1\]

    C)  \[7\]                                    

    D)  \[2.7\]

    Correct Answer: A

    Solution :

                    \[{{H}^{+}}+{{e}^{-}}\xrightarrow{{}}\frac{1}{2}{{H}_{2}}\] \[{{E}_{cell}}={{E}^{o}}_{cell}-0.0591\log \frac{1}{{{H}^{+}}}\] \[-0.118V=0+0.0591\,[{{H}^{+}}]\] \[-0.118V=0+0.0591\{-\log [{{H}^{+}}]\}\] \[-0.118V=-0.0591pH\] \[pH=\frac{0.118}{0.0591}=2\]


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