A) \[1.3{}^\circ C/min\]
B) \[1.4{}^\circ C/min\]
C) \[1.5{}^\circ C/min\]
D) \[1.8{}^\circ C/min\]
Correct Answer: D
Solution :
\[{{\left( \frac{\text{d }\!\!\theta\!\!\text{ }}{\text{dt}} \right)}_{\text{1}}}\text{=K(}{{\text{ }\!\!\theta\!\!\text{ }}_{\text{1}}}\text{-}{{\text{ }\!\!\theta\!\!\text{ }}_{\text{0}}}\text{)}\]...(i) \[{{\left( \frac{\text{d }\!\!\theta\!\!\text{ }}{\text{dt}} \right)}_{2}}\text{=K(}{{\text{ }\!\!\theta\!\!\text{ }}_{2}}\text{-}{{\text{ }\!\!\theta\!\!\text{ }}_{\text{0}}}\text{)}\]...(ii) \[\therefore \]\[\frac{{{(d\theta /dt)}_{1}}}{{{(d\theta /dt)}_{2}}}=\frac{{{\theta }_{1}}-{{\theta }_{2}}}{{{\theta }_{2}}-{{\theta }_{0}}}=\frac{50-25}{40-25}\] \[\frac{3}{{{(d\theta /dt)}_{2}}}\frac{25}{15}\] \[\Rightarrow \]\[\,{{\left( \frac{d\theta }{dt} \right)}_{2}}={{1.8}^{0}}c/\min \]
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