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Haryana PMT Haryana PMT Solved Paper-2011

  • question_answer
    \[10\text{ }g\]of a non-volatile solute when dissolved in \[100g\]of benzene raises its boiling point by \[{{1}^{o}}\]. What is the molecular mass of the solute? (\[{{K}_{b}}\] for benzene \[=2.53\,k{{m}^{-1}}\])

    A)  \[352\]                                

    B)  \[253\]  

    C)  \[275\]                                

    D)  \[310\]

    Correct Answer: B

    Solution :

                    \[{{w}_{1}}=100g,\]         \[{{w}_{2}}=10g,\] \[\Delta {{T}_{b}}={{1}^{o}},\,{{K}_{b}}=2.53\,K{{m}^{-1}}\] \[{{M}_{2}}=\frac{1000{{K}_{b}}\times {{w}_{2}}}{{{w}_{1}}\times \Delta {{T}_{b}}}\] \[=\frac{1000\times 2.53\times 10}{100\times 1}\]


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