A) \[C{{H}_{2}}=C{{H}_{2}}\]
B)
C)
D)
Correct Answer: D
Solution :
According to Markownikoff 's rule the addition of a reagent (HX) to an unsymmetrical alkene takes place in such a way that the negative part of the reagent will be attached to that carbon atom which contains lesser number of H-atom. \[\underset{2-\text{methylpropene}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}+HBr}}\,\xrightarrow{{}}C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{Br}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-C{{H}_{3}}\]
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