A) 1-butanol
B) 2-butanol
C) 3-pentanol
D) 4-heptanol
Correct Answer: B
Solution :
A carbon atom which is attached to four different groups is called an asymmetric carbon atom or chiral centre and a compound which contain a chiral carbon atom is called optically active compound. \[\underset{\text{butan}-2-ol\,or\,2-\text{butanol}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\underset{OH}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{{{C}^{*}}}}}\,}}}\,-C{{H}_{3}}}}\,\] Hence, 2-butanol can exist in optically active form.
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