A) \[{{(m+1)}^{n}}\]
B) \[\frac{(mn)!}{{{(m!)}^{n}}}\]
C) \[^{mn}{{C}_{n}}{{\times }^{n}}{{C}_{1}}\]
D) \[{{(m+n)}^{n}}-1\]
Correct Answer: D
Solution :
There are \[(m+1)\]choices for each of n different books. So, the total number of choices is \[{{(m+1)}^{n}}\] including one choice in which we do not select any book. Hence, the required number of ways is \[{{(m+1)}^{n}}\].
You need to login to perform this action.
You will be redirected in
3 sec
