A) \[15\]
B) \[21\]
C) \[12\]
D) \[31/48\]
Correct Answer: D
Solution :
Since, \[\frac{2}{3},k\] and \[\frac{5}{8}\]are in AP. \[\therefore \] \[2k=\frac{2}{3}+\frac{5}{8}\Rightarrow k=\frac{31}{48}\]
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