J & K CET Engineering J and K - CET Engineering Solved Paper-2003

  • question_answer
    If \[x=\sqrt{3018+\sqrt{36+\sqrt{169}}},\] then the value of x is

    A) \[55\]           

    B)  \[44\]

    C)  \[63\]            

    D)  \[42\]

    Correct Answer: A

    Solution :

    Given that, \[x=\sqrt{3018+\sqrt{36+\sqrt{169}}}\] \[=\sqrt{3018+\sqrt{36+13}}=\sqrt{3018+7}\] \[=\sqrt{3025}=55\]


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