A) \[1050\text{ }W\]
B) \[2100\text{ }W\]
C) \[1500\text{ }W\]
D) \[3000\text{ }W\]
Correct Answer: A
Solution :
Power is the amount of work done or energy (Q ) transferred per unit of time (t). \[\therefore \] \[P=\frac{H}{t}\] \[H=mc\,\Delta \theta \] where m is mass, c the specific heat and \[\,\Delta \theta \] the temperature difference. \[\therefore \] \[P=\frac{mc\,\Delta \theta }{t}\] \[\Delta \theta ={{(35-20)}^{o}}C={{15}^{o}}C\] \[C=1000,\,\,\,\,4.2J=1cal\] \[t=1\min =60s\] \[\therefore \] \[P=\frac{1\times 1000\times 15\times 4.2}{60}J/s=1050W\]
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