A) \[k={{e}^{-E/RT}}\]
B) \[k=\ln \frac{E}{RT}\]
C) \[k=\frac{A.E}{RT}\]
D) \[k=A.{{e}^{-{{E}_{a}}/RT}}\]
Correct Answer: D
Solution :
Arrhenius proposed a quantitative relationship between the rate constant and temperature as: \[k=A{{e}^{-{{E}_{a}}/RT}}\] where, A = frequency factor \[{{E}_{a}}=\]activation energy
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