J & K CET Engineering J and K - CET Engineering Solved Paper-2004

  • question_answer
    \[\text{KI}\]and \[\text{CuS}{{\text{O}}_{\text{4}}}\]solution when mixed gives

    A)  \[Cu{{l}_{2}}+{{K}_{2}}S{{O}_{4}}\]

    B) \[C{{u}_{2}}{{I}_{2}}+{{K}_{2}}S{{O}_{4}}\]

    C)  \[{{K}_{2}}S{{O}_{4}}+C{{u}_{2}}{{I}_{2}}+{{I}_{2}}\]

    D)  \[{{K}_{2}}S{{O}_{4}}+Cu{{I}_{2}}+{{I}_{2}}\]

    Correct Answer: C

    Solution :

     Copper sulphate reacts with KI to give cuprous iodide and iodine. \[\underset{\begin{smallmatrix}  \text{copper} \\  \text{sulphate} \end{smallmatrix}}{\mathop{2CuS{{O}_{4}}}}\,+4KI\to \underset{\begin{smallmatrix}  \text{cuprous} \\  \text{iodide} \end{smallmatrix}}{\mathop{C{{u}_{2}}{{I}_{2}}}}\,+\underset{\text{iodine}}{\mathop{{{I}_{2}}}}\,+2{{K}_{2}}S{{O}_{4}}\]


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