A) \[6.02\times {{10}^{23}}\]
B) \[12.04\times {{10}^{22}}\]
C) \[1.806\times {{10}^{23}}\]
D) \[31.80\times {{10}^{2}}\]
Correct Answer: C
Solution :
Molecular mass of \[\text{N}{{\text{a}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}\] \[=2\times 23+12+3\times 16=106\] \[\because \]\[\text{106}\,\text{g}\,\text{N}{{\text{a}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}\] contains \[\text{=}\,\text{3}\times 6.023\times {{10}^{23}}\]oxygen atoms \[\therefore \]\[10.6\,g\]of \[\text{N}{{\text{a}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}\]will contain \[\text{=}\frac{3\times 6.023\times {{10}^{23}}}{106}\times 10.6\] \[=18.069\times {{10}^{22}}\] \[=1.806\times {{10}^{23}}\] oxygen atoms
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