A) \[\text{9}\text{.315 MeV}\]
B) \[\text{ }\!\!~\!\!\text{ 931}\text{.5 MeV}\]
C) \[\text{ }\!\!~\!\!\text{ 83}\text{.0 MeV}\]
D) \[\text{ }\!\!~\!\!\text{ 8}\text{.38 MeV}\]
Correct Answer: A
Solution :
\[\Delta m=0.090\,u\] Number of nucleon \[=9\] \[\therefore \]Binding energy per nucleon \[=\frac{\text{total}\,\text{binding}\,\text{energy}}{\text{number}\,\text{of}\,\text{nucleon}}\] \[\text{=}\frac{\text{ }\!\!\Delta\!\!\text{ m}\,\text{ }\!\!\times\!\!\text{ }\,\text{931}\text{.5}}{\text{number}\,\text{of}\,\text{nucleon}}\] \[=\frac{0.090\times 931.5}{9}=9.315\,MeV\]
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