A) increase of one neutron only
B) decrease of one neutron only
C) both [a] and [b]
D) none of the above
Correct Answer: B
Solution :
Loss of a\[\beta -\]particle is equivalent to decrease of one neutron only. \[n\xrightarrow{{}}p+{{e}^{-}}+\bar{v}\] Hence, by the emission of a \[\beta -\]particle atomic number is increased by one unit.
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