A) \[Xe{{F}_{2}}\]
B) \[Xe{{O}_{3}}F\]
C) \[Xe{{O}_{2}}{{F}_{2}}\]
D) \[Xe{{F}_{4}}\]
Correct Answer: A
Solution :
\[\text{Xe}{{\text{F}}_{\text{2}}}\]molecule contains two bond pairs and three lone pairs in the outer-shell of central atom and thus its hybridisation is\[s{{p}^{3}}{{d}^{2}}\] but to minimize the repulsive forces the three lone pairs occupy the equatorial position and the molecule becomes linear shape.
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