A) Methane
B) Acetylene
C) 1-butene
D) Neo-pentane
Correct Answer: B
Solution :
In \[{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}\]each C-atom is sp-hybridised which contains 50% \[s-\]character. The greater the 5- character of an orbital, the bonding .electron pair will be more inclined towards the nucleus as a result carbon would acquire a negative charge and hydrogen a positive charge. Hence, it is acidic in nature. \[H-\underset{sp}{\mathop{C}}\,\equiv \underset{sp}{\mathop{C}}\,:H\] and removal of hydrogen as proton takes place.
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