A) \[3/10\]
B) \[4/5\]
C) \[1/2\]
D) \[1/6\]
Correct Answer: B
Solution :
Total no. of defective items is 3. \[\therefore \] \[P(0<X<3)=\frac{^{3}{{C}_{1}}{{\times }^{7}}{{C}_{3}}}{^{10}{{C}_{4}}}+\frac{^{3}{{C}_{2}}{{\times }^{7}}{{C}_{2}}}{^{10}{{C}_{4}}}\] \[=\frac{3\times 35}{210}+\frac{3\times 21}{210}\] \[=\frac{105}{210}+\frac{63}{210}=\frac{168}{210}=\frac{4}{5}\]
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