J & K CET Engineering J and K - CET Engineering Solved Paper-2005

  • question_answer
    A proton, a deuteron and an alpha particle are accelerated through same potential difference and then they enter a normal uniform magnetic field. The ratio of their kinetic energies will be

    A)  \[2:1:3\]     

    B)  \[1:1:2\]

    C)  \[1:1:1\]     

    D)  \[1:2:4\]

    Correct Answer: B

    Solution :

    When a particle with charge q passes through a potential difference V, then kinetic energy acquired by particle is \[K=qV\] Given,   \[{{q}_{1}}:{{q}_{2}}:{{q}_{3}}=1:1:2\] and     \[{{V}_{1}}:{{V}_{2}}:{{V}_{3}}=1:1:1\] \[\therefore \] \[{{K}_{1}}:{{K}_{2}}:{{K}_{3}}=1:1:2\]


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