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J & K CET Engineering J and K - CET Engineering Solved Paper-2005

  • question_answer
    The particle A is converted into C via following reaction, \[A\xrightarrow{{}}B{{+}_{2}}H{{e}^{4}}\] \[B\xrightarrow{{}}C+2{{e}^{-}}\] Then

    A)  A and C are isobars

    B)  A and C are isotopes

    C)  A and B are isobars

    D)  A and B are isotopes

    Correct Answer: B

    Solution :

    Let x be the mass number of A and y the atomic number. Then, since atomic number and mass number remain conserved, we have \[_{y}{{A}^{x}}{{\xrightarrow{{}}}_{2}}{{B}^{x-4}}{{+}_{2}}H{{e}^{4}}\] \[_{y-2}{{B}^{x-4}}{{\xrightarrow{{}}}_{y}}{{C}^{x-4}}+{{2}_{-1}}{{e}^{0}}\] Hence, we observe that A and C are isotopes as their atomic numbers are same but mass numbers are different.


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