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J & K CET Engineering J and K - CET Engineering Solved Paper-2006

  • question_answer
    The line perpendicular to the plane s\[2x-y+5z=4\] passing through the point \[(-1,0,1)\] is

    A)  \[\frac{x+1}{2}=-y=\frac{z-1}{-5}\]

    B)  \[\frac{x+1}{2}=-y=\frac{z-1}{-5}\]

    C)  \[\frac{x+1}{2}=-y=\frac{z-1}{5}\]

    D)  \[\frac{x+1}{2}=y=\frac{z-1}{5}\]

    Correct Answer: C

    Solution :

    The line perpendicular to the plane \[2x-y+5z=4\] and passing through the point \[(-1,0,1)\] is given by \[\frac{x+1}{2}=\frac{y-0}{-1}=\frac{z-1}{5}\] \[\Rightarrow \]\[\frac{x+1}{2}=-y=\frac{z-1}{5}\]


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